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Suppose that 6% of the people with blood group O are left handed and 10% of those with other blood groups are left handed 30% of the people have blood group O.If a left handed person is selected at random,what is the probability that he/she will have blood group O?

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Let\(E_1\) be a person selected be 'o' group
\(E_2\) be a person selected be of non 'o' group
A; He is left handed person
P(\(E_1/A\))=P(\(he\; is\; 'o' \;group/he \;is\; left \;handed\))
P\(E_1\)=P(He is 'o' group)=\(\large\frac{30}{100}\)=\(\large\frac{3}{10}\)
P\(E_2\)=P(He isnot 'o' group)=\(\large\frac{70}{100}\)=\(\large\frac{7}{10}\)
P(\(A/E_1\))=P(He is left handed /he is'O' groyp)
P(\(A/E_2\))=P(He is left handed /he is not 'O' groyp)


answered Mar 1, 2013 by poojasapani_1
edited Jun 4, 2013 by poojasapani_1

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