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There is a point object and a plane mirror . If the mirror is moved by 10 cm away from object , find distance which the image will move by

$(a)\;10\;cm \\ (b)\;20\;cm \\ (c)\;30\;cm \\ (d)\;40\;cm $

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We know that $X_{im}=-X_{om}$
or $X_i -X_m=X_m -X_0$
or $\Delta x_i -\Delta x_m=\Delta x_m -\Delta x_0$
here $\Delta x_0 =0$
$\Delta x_m=10$
$\therefore \Delta_x= 2 \Delta x_m-\Delta x_0=20\;cm$
Hence b is the correct answer.
answered Feb 10, 2014 by meena.p

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