$\begin{array}{1 1} 1299038 \;J \\ 1345798 \;J \\ 2345012\;J \\ 19939038\;J \end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

- $\overrightarrow a.\overrightarrow b=|\overrightarrow a|\:|\overrightarrow b|\:cos\theta$

Given the Force, $\overrightarrow F$ and Distance $\overrightarrow D$ vectors, we can write the work done as $\overrightarrow W = \overrightarrow F . \overrightarrow D$

$\overrightarrow a.\overrightarrow b=|\overrightarrow a|\:|\overrightarrow b|\:cos\theta$

$\Rightarrow$$\;\overrightarrow W = \overrightarrow F . \overrightarrow D = | \overrightarrow F| \:|\overrightarrow D| \:cos \theta$

In our case $\theta = 30 ^{0} = \large\frac{\pi}{6}$

$\Rightarrow$$\;\overrightarrow W = | \overrightarrow F| \: |\overrightarrow D| \:cos \theta = 1500N \times 1000m \times \cos \large(\frac{\pi}{6})$

$\Rightarrow \overrightarrow W = 750000 \sqrt 3 J \approx 1299038 J$

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...