(a)both (i) and (iv)

(b)both (i) and (iii)

(c) both (ii) and (iii)

(d) both (ii) and (iv)

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Focal length $F= -f$

and $u=-1.5\;f$

$\large\frac{1}{u}+\frac{1}{v}=\frac{1}{F}$

$\large\frac{1}{-1.5 \;f}+\frac{1}{v}=\frac{-1}{f}$

$\large\frac{1}{v}=\frac{1}{1.5 f}-\frac{1}{f}$

$\qquad= -\large\frac{-1}{3f}$

$v= -3 f$

Now $m =\large\frac{-v}{u}=\frac{-3 f}{1.5 \;f}$$=-2$

or $\large\frac{h_2}{h}$$=-2$

or $h_2=-2 h_1=-5 cm$

the image is 5 cm long.

The minus sign shows that it is inverted.

Hence c is the correct answer.

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