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The electrostatic potential due to the charge configuration at point P as shown in figure is $\;(b < < a)$


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Answer : (c) $\;\large\frac{k\;q\;b^2}{a^3}$
Explanation :
Using binomial expansion
$=\large\frac{2\;k\;q}{a}-\large\frac{2\;k\;q}{a}\;[1-\large\frac{1}{2} \large\frac{b^2}{a^2}]$
answered Feb 11, 2014 by yamini.v

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