logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

If a luminous point is moving at a speed $V_0$ towards spherical mirror of focal length f along its axis, Find the speed of image.

$(a)\;\frac{-f V_0}{u- f} \\ (b)\;\bigg[\frac{f}{u+ f}\bigg]^2 V_0 \\ (c)\;\bigg[\frac{f}{u- f}\bigg]^2. v_0 \\ (d)\;- \bigg[\frac{f}{u- f}\bigg]^2 V_0 $

Can you answer this question?
 
 

1 Answer

0 votes
As we know,
$\large\frac{1}{v}+\frac{1}{u} =\frac{1}{f}$
differentiating with respect to time
we obtain , $-\large\frac{-1}{V^2} \frac{dv}{dt} -\frac{1}{u^2} \frac{du}{dt}$$=0$
or $\large\frac{-1}{V^2} V_{image}- \large\frac{1}{u^2} V_{object}=0$
But from mirror equation $v= \large\frac{uf}{u-f}$
So $V_{image}= - \bigg(\large\frac{V}{u} \bigg)^2 V_{object}$
$\qquad= - \bigg[ \large\frac{f}{u-f}\bigg]^2 V_0$
Hence d is the correct answer.
answered Feb 11, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...