Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

$HNO_3$ used as a reagent has specific gravity of $1.42 mL^{-1}$ and contains $70\%$ by strength $HNO_3$. Calculate Volume of acid that contains 63g pure acid.

$(a)\;60 mL\qquad(b)\;63.38mL\qquad(c)\;65mL\qquad(d)\;70mL$

Can you answer this question?

1 Answer

0 votes
Strength of $HNO_3 = 70\%$
Volume of solution = 100mL
Volume of $HNO_3$ = 70mL
Specific gravity of $HNO_3 = 1.42gmL^{-1}$
Since $70\times1.42g$ of pure acid is present in 100mL
$\therefore$ 63g of pure acid present in = $\large\frac{100\times63}{70\times1.42}$
=63.38 mL
Hence answer is (b)
answered Feb 11, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App