$(a)\;\sin ^{-1}1 \\ (b)\;\sin ^{-1} \frac{1}{2} \\ (c)\;\sin ^{-1} \frac{1}{1.3}\\ (d)\;\sin ^{-1} \frac{1}{2.6} $

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As we know that

$y \sin 1$= constant

=> $ y +{air} -\sin _{i(air)}= y _{glass} \sin r _{glass)}$

$\sin i (glass) =\large\frac{y_{air}}{y_{glass}}$$\sin i_{air}$

Again $y_{glass} \sin i_{(glass)}=y _{water} \sin r_{water}$

From (i) and (ii)

$\qquad= \sin 30 =1.3 \sin r$

$\sin r =\large\frac{1}{2 \times 1.3} =\frac{1}{2.6};$

$r=\sin ^{-1} \large\frac{1}{2.6}$

Hence d is the correct answer.

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