Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
0 votes

Find the length of tangents drawn from the point (4,5) to the circle $x^2+y^2+3x-2y-11=0$?

$\begin{array}{1 1}(a)\;\sqrt{32}&(b)\;\sqrt{12}\\(c)\;\sqrt{30}&(d)\;\sqrt{22}\end{array}$

Can you answer this question?

1 Answer

0 votes
The equation of given circle is $x^2+y^2+3x-2y-11=0$
Now $S_1=(4)^2+(5)^2+3(4)-2(5)-11=32$
Length of tangent $=\sqrt{S_1}$
$\Rightarrow \sqrt{32}$
Hence (a) is the correct answer.
answered Feb 11, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App