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Calculate the volume occupied by 7g $N_2$ at $27^{\large\circ}$ and 750mm of Hg.

$(a)\;5.369 litres\qquad(b)\;4.369 litres\qquad(c)\;6.239 litres\qquad(d)\;3.369litres$
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Given
W = 7g
T = 300K
P = $\large\frac{750}{760} atm$
and m = 28
Now PV = $\large\frac{w}{m} RT$
R = 0.0821 l atm $K^{-1} mol^{-1}$
PV = $\frac{7}{28}\times0.0821\times300$
V = $\frac{7}{28}\times0.0821\times300\times\frac{760}{750}$
V = 6.239 litres
Hence answer is (c)
answered Feb 11, 2014 by sharmaaparna1
 

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