$(a)\;2\pi \sqrt{\large\frac{I}{PE}}\qquad(b)\;\pi \sqrt{\large\frac{I}{PE}}\qquad(c)\;\pi \sqrt{\large\frac{PE}{I}}\qquad(d)\;2\pi \sqrt{\large\frac{PE}{I}}$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Answer : (a) $\;2\pi \sqrt{\large\frac{I}{PE}}$

Explanation :

When displaced at an angle $\;theta$, from its mean position the magnitude of restoring torque is

$\tau=-P sin \theta$

For small angular displacement $\;sin \theta \approx \theta$

$\tau=-P E \theta$

$\alpha =\large\frac{\tau}{I}=-(\large\frac{PE}{I})\;\theta=-w^2 \theta$

$w^2=\large\frac{P E}{I}$

$T=2 \pi \sqrt{\large\frac{I}{PE}}\;.$

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...