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Value of gas Constant R is

$\begin {array} {1 1} (a)\;0.082\; litre\; atm K^{-1}mol^{-1}\\(b)\;0.987\;Cal \;mol^{-1}\;K^{-1}\\(c)\;8.35\; mol^{-1}\;K^{-1}\\(d)\;83 \;erg\; mol^{-1}\;K^{-1}\end {array}$

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$R = 8.3 J Mol^{-1}K^{-1}$
= 2 cal $mol^{-1}K^{-1}$
$=8.314\times10^7$ erg $mol^{-1}K^{-1}$
= 0.082 litre atm $K^{-1}mol^{-1}$
Hence answer is (a)
answered Feb 12, 2014 by sharmaaparna1

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