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# As the temperature is raised from $20^{\large\circ}C \;to \;40^{\large\circ}C$ , the average kinetic energy of neon atoms changes by a factor.

$(a)\;2\qquad(b)\;\sqrt{\large\frac{313}{293}}\qquad(c)\;\large\frac{313}{293}\qquad(d)\;\large\frac{1}{2}$

Can you answer this question?

Kinetic Energy = $\large\frac{3}{2}RT$
$E_1 = \large\frac{3}{2}\times R\times293$
$E_2 = \large\frac{3}{2}\times R\times313$
$E_2 = \large\frac{313}{293}\times E_1$
Hence answer is (c)
answered Feb 12, 2014