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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
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Molarity of NaOH solution containing 5g of NaOH in 450ml of solution?

$\begin{array}{1 1}(a)\;0.278mol.cm^{-3}\\(b)\;0.134mol.cm^{-3}\\(c)\;0.278mol.L^{-1}\\(d)\;0.134mol.dm^{-3}\end{array}$

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Answer: $ 0.278 \; mol\;L^{-1}$
Molarity (M) is defined as number of moles of solute dissolved in one litre (or one cubic decimetre) of solution, $M = \large\frac{\text{ Moles of solute }}{\text{Molarity Volume of solution in litre}}$
Molarity Volume of solution in litre for $NaOH = 450\; mL = 0.45\;L$
Moles of $NaOH$ solute $= \large\frac{5\;g}{40\;g\;mol^{-1}}$$ = 0.125\;mol$
$\Rightarrow$ Molarity $M = \large\frac{0.125\;mol}{ 0.45\;L} $$= 0.278 \; mol\;L^{-1}$
answered Feb 12, 2014 by sreemathi.v
edited Jul 16, 2014 by balaji.thirumalai
 

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