$\begin{array}{1 1}(a)\;16N\\(b)\;26N\\(c)\;36N\\(d)\;46N\end{array}$

Answer: 36 N

Molarity (M) is defined as number of moles of solute dissolved in one litre (or one cubic decimetre) of solution, $M = \large\frac{\text{ Moles of solute }}{\text{Molarity Volume of solution in litre}}$

Normality is the product of the molarity of the solution times the number of valences taking place in a reaction.

Let the Volume be $ V = 1\;L = 1000\;mL$ Therefore mass of the solution $ = 1.8 \times 1000 = 1800\;g$

Mass of the solute $= 98\; \%\; \text{of}\; 1800 = 1764\;g$ and Molarity volume of solution in liter $= 98\;L$

$\Rightarrow$ Molarity $M = \large\frac{1764}{98}$$ = 18M$

Valence of $H_2SO_4 = 2$

$\Rightarrow$ Normality $ = 2 \times 18 = 36\;N$

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