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What is mass percentage of benzene $(C_6H_6)$ in carbon tetrachloride $(CCl_4)$ if 20g of benzene is dissolved in 180g of $CCl_4$?

$\begin{array}{1 1}(a)\;10\%\\(b)\;9\%\\(c)\;2\%\\(d)\;8\%\end{array}$

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Answer: 10%
Mass percentage $= \large\frac{\text{mass of benzene}}{\text{mass of solution}}$$\times 100\%$
Mass of Benzene = 20g, Total mass of the solution = 20 + 180 = 200g.
$\Rightarrow$ Mass percentage $ = \large\frac{20}{200} \% $$= 10\%$
answered Feb 12, 2014 by sreemathi.v
edited Jul 16, 2014 by balaji.thirumalai
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