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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
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If 50ml of 0.5M $H_2SO_4$ is diluted to 1000 ml, what is the molarity of diluted solution?

$\begin{array}{1 1}(a)\;0.05M\\(b)\;0.50M\\(c)\;0.25M\\(d)\;0.025M\end{array}$

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Answer: 0.025 M
The number of moles of solute in the concentrated solution is equal to the number of moles in the dilute solution $\rightarrow M_1\;V_1 = M_2\;V_2$ where 1 and 2 stand for the concentrated and diluted solutions.
Given, $M_1 = 0.5M,\; V_1 = 50\;mL, V_2 = 1000\;mL$ substituting, we get
$M_2 = \large\frac{M_1\;V_1}{V_2}$$ = \large\frac{0.5 \times 50}{1000}$$ = 0.025\;M$
answered Feb 12, 2014 by sreemathi.v
edited Jul 16, 2014 by balaji.thirumalai
 

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