$\begin{array}{1 1}(a)\;150g\\(b)\;120g\\(c)\;170g\\(d)\;200g\end{array}$

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Answer: $ 145.63\;g$

Molar Mass of Urea $(NH_2CONH_2) = 2 (1\times14+2\times)+1\times12+1\times16 = 60\;g\;mol^{-1}$

0.5 molar aques solution of urea mass implies that 1000 g of water contains 0.5 mol $= 0.5 \times 60 = 30\;g$ of urea.

$(1000+30)\; g$ of solution contains $30\;g$ of urea $\rightarrow 5\;kg (5000\;g)$ of solution will contain $\large\frac{30 \times 5000}{1000+30}$$ = 145.63\;g$

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