If the molar mass of glucose is 180.2 g mol$^{-1}$ and if 36 gm of glucose $C_6H_{12}O_6$ is present in 1000 gm of an aqueous solution of glucose,it is said to be

$\begin{array}{1 1}(a)\;1molal\\(b)\;2molal\\(c)\;0.5molal\\(d)\;0.2molal\end{array}$

Molality by definition is the number of gram moles of a substance per 1000 grams of solvent.
Number of moles of glucose = $\large\frac{36}{180}$$= 0.2 \Rightarrow Molality = \large\frac{0.2\; mol}{1\;Kg}$$ = 0.2$ molal.
edited Jul 16, 2014