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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
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If the molar mass of glucose is 180.2 g mol$^{-1}$ and if 36 gm of glucose $C_6H_{12}O_6$ is present in 1000 gm of an aqueous solution of glucose,it is said to be

$\begin{array}{1 1}(a)\;1molal\\(b)\;2molal\\(c)\;0.5molal\\(d)\;0.2molal\end{array}$

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1 Answer

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Answer: 0.2 molal.
Molality by definition is the number of gram moles of a substance per 1000 grams of solvent.
Number of moles of glucose = $\large\frac{36}{180}$$ = 0.2$
$\Rightarrow$ Molality $ = \large\frac{0.2\; mol}{1\;Kg}$$ = 0.2$ molal.
answered Feb 12, 2014 by sreemathi.v
edited Jul 16, 2014 by balaji.thirumalai
 
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