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Home  >>  CBSE XII  >>  Math  >>  Probability
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If $P(A)=\Large\frac{4}{5}$,and $P(A\cap B)=\Large\frac{7}{10}$,then P(B|A) is equal to

$\begin{array}{1 1}(A)\;\frac{1}{10}\quad(B)\;\frac{1}{8}\quad(C)\;\frac{7}{8}\quad(D)\;\frac{17}{20}\end{array} $

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1 Answer

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  • P(B/A)=\(\frac{P(B\cap\;A)}{P(A)}\)
P(A)=\(\frac{4}{5}\)
P(A\(\cap\)B)=\(\frac{7}{10}\)
P=(B/A)=\(\frac{7}{10}\)\(\times\)\(\frac{5}{4}\)
=\(\frac{7}{8}\)
'C'is correct

 

answered Feb 23, 2013 by poojasapani_1
edited Jun 4, 2013 by poojasapani_1
 

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