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Home  >>  CBSE XII  >>  Math  >>  Probability
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If $P(A\cap B)=\Large\frac{7}{10}$,and $P( B)=\Large\frac{17}{20}$,then P(A|B) is equals

$\begin{array}{1 1}(A)\;\frac{14}{17}\quad(B)\;\frac{17}{20}\quad(C)\;\frac{7}{8}\quad(D)\;\frac{1}{8}\end{array} $

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1 Answer

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Toolbox:
  • P=(A/B)=\(\frac{P(A(\cap)B)}{P(B)}\)
P(A\(\cap\)B)=\(\frac{7}{10}\)
P(B)=\(\frac{17}{20}\)
P(A/B)=\(\frac{7}{10}\)\(\times\)\(\frac{20}{17}\)
=\(\frac{14}{11}\)
'A"option is correct

 

answered Feb 23, 2013 by poojasapani_1
edited Jun 4, 2013 by poojasapani_1
 

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