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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
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If 200 mL of 0.1 M urea solution is mixed with 300 mL of 0.2 M Glucose solutions at 300 K calculate osmotic pressure.

$\begin{array}{1 1} 3.9408\;atm \\ 3.4208\;atm \\ 2.4634 \;atm \\ 2.6673 \;atm \end{array}$
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Answer: 3.9408 atm
If $V_1$ mL of $C_1$ solution and $V_2$ mL of $C_2$ solution are mixed together, then the net osmotic pressure $\pi = CRT$, where $C = \large\frac{C_1V_1+C_2V_2}{V_1+V_2}$
In our case, $C = \large\frac{0.1 \times 200 + 0.2 \times 300}{ 200+300}$$ = 0.16\;M$
$\Rightarrow \pi = 0.16 \times 0.0821 \times 300 = 3.9408\; atm$
answered Feb 13, 2014 by sreemathi.v
edited Jul 16, 2014 by balaji.thirumalai
 

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