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X mL of $H_2$ gas effuses through a hole in a container is 5 Second. The time taken for the effusion of the same Volume of the gas Specified below under identical conditions is

$(a)\;10 Seconds ; He\qquad(b)\;20 Seconds ; O_2\qquad(c)\;25 Seconds ; CO\qquad(d)\;55 Seconds ; CO_2$

1 Answer

$\large\frac{X}{5}\times\large\frac{t}{X} = \sqrt{\large\frac{32}{2}}$
For $H_2$ and $O_2$
$\therefore t = 20 Second$
Hence answer is (b)
answered Feb 13, 2014 by sharmaaparna1

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