logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

According to Graham's law , at a given temperature , the ratio of rates of diffusion $\large\frac{r_A}{r_B}$ of gases A and B is given by:

$\begin {array} {1 1} (a)\;(\large\frac{P_A}{P_B})(\large\frac{M_A}{M_B})^{\frac{1}{2}}\\(b)\;(\large\frac{M_A}{M_B})(\large\frac{P_A}{P_B})^{\frac{1}{2}}\\(c)\;(\large\frac{P_A}{P_B})(\large\frac{M_B}{M_A})^{\frac{1}{2}}\\(d)\;(\large\frac{M_A}{M_B})(\large\frac{P_B}{P_A})^{\frac{1}{2}} \end {array}$

Can you answer this question?
 
 

1 Answer

0 votes
According to Graham's law
We have
$\large\frac{r_1}{r_2} = \sqrt{\large\frac{M_2}{M_1}}\times\large\frac{P_1}{P_2}$
Hence we can write as
$=(\large\frac{P_A}{P_B})(\large\frac{M_B}{M_A})^{\frac{1}{2}}\qquad$
Thus the answer is (c)
answered Feb 13, 2014 by sharmaaparna1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...