$(a)\;6cm^3\qquad(b)\;60cm^3\qquad(c)\;0.6cm^3\qquad(d)\;0.06cm^3$

Given

Density of liquid water = 1.0g $cm^{-3}$

Density of water vapour = 0.0006g $cm^{-3}$

Mass of 1000mL steam = $1000\times0.0006 = 0.6g$

Since, Volume of liquid water = $\large\frac{\text{Mass of 1000mL steam}}{\text{Density of liquid water}} = \large\frac{0.6g}{1g\;cm^{-3}}$

$\therefore$ Volume of liquid water = $0.6 cm^3$

Hence answer is (c)

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