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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
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In the circuit shown, potential difference between the points A and B is $16V$. The current passing through the $2\Omega$ resistor will be

 

$\begin {array} {1 1} (A)\;3A & \quad (B)\;3.5A \\ (C)\;4.5A & \quad (D)\;Zero \end {array}$

 

Can you answer this question?
 
 

1 Answer

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Assume the values of current in the main branch as well as in the loop.
Write equations of KCL and KVL for the loop and the branch.
Let the current in the 2 ohm resistor be $i_1 + i_2$
then using KVL equation in closed loop
$ 9 - i_2 - 2(i_1 +i_2 ) = 0 $ ........................(1)
$4 i_1 +2 (i_1 +i_2 ) -3 +4 i_1 = 16 $ ................(2)
solving we get $i_1 =1.5$ and $i_2 = 2$
Thus current through 2 ohm resistor is 3.5 ohms
Ans : (B)
answered Feb 13, 2014 by thanvigandhi_1
edited Sep 11, 2014 by meena.p
 

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