logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Wave Optics
0 votes

Light from two sources , each of same frequency and travelling in same direction. but with intensity in ratio 4:1 interface. Find ratio of maximum to minimum intensity.

$(a)\;4:1 \\ (b)\;3:1 \\ (c)\;2:1 \\ (d)\; 9:1 $

Can you answer this question?
 
 

1 Answer

0 votes
$\large\frac{I_{max}} {I_{min}}$$ = \bigg(\large\frac{\sqrt {I_1}+ \sqrt {I_2}}{\sqrt {I_1}- \sqrt {I_2}}\bigg)^2$
$\qquad= \bigg[\large \frac{\sqrt {\frac {I_1}{I_2}} +1}{\sqrt {\frac{I_1}{I_2}}-1}\bigg]^2$
$\qquad=9:1$
Hence d is the correct answer.

 

answered Feb 13, 2014 by meena.p
edited Jul 23, 2014 by thagee.vedartham
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...