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Let $P(A)=\Large\frac{7}{13}$,$P(B)=\Large\frac{9}{13}$ and $P(A\cap B)=\Large\frac{4}{13}$. Then P(A|B) is equal to

$\begin{array}{1 1}(A)\;\large\frac{6}{13}\\(B)\;\large\frac{4}{13}\\(C)\;\large\frac{4}{9}\\(D)\;\large\frac{5}{9}\end{array} $

1 Answer

Toolbox:
  • \(P(A/B)=\frac{p(A\cap\;B)}{P(B)}\;\;\;\;\;=\;p(A/B)=\huge\frac{\frac{4}{13}}{\frac{9}{13}}\)
\(P(A/B)=\large\frac{4}{9}\)

'C'option is correct

answered Feb 22, 2013 by poojasapani_1
edited Mar 15, 2013 by poojasapani_1
 
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