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Questions  >>  CBSE XII  >>  Math  >>  Probability
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Let $P(A)=\Large\frac{7}{13}$,$P(B)=\Large\frac{9}{13}$ and $P(A\cap B)=\Large\frac{4}{13}$. Then P(A|B) is equal to

$\begin{array}{1 1}(A)\;\large\frac{6}{13}\\(B)\;\large\frac{4}{13}\\(C)\;\large\frac{4}{9}\\(D)\;\large\frac{5}{9}\end{array} $

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