$(a)\;(4,5) \\ (b)\;(5,4) \\ (c)\;(3,4) \\ (d)\;(4,3) $

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Maximum path difference $\Delta P_{max}=d= 1mm$

=> highest order maxima,

$n_{max} =\bigg[\large\frac{d}{\lambda} \bigg]$$=2$

and highest order minima $n_{min}= \bigg[ \large\frac{d}{\lambda} +\frac{1}{2}\bigg]$

$\qquad= 2$

Total number of maxima $=2 n _{max} +1=5$

Total number of minima $=2n _{min}=4$

Hence the correct answer is b

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