Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Wave Optics
0 votes

Monochromatic light of wavelength $5000\;A^{\circ} $ is used in Y.D.S.E with slit- width $d= 1 mm$distance between screen and slits $D=1\;m$ .Then the distance of 5th minima from central maxima on screen is :-

$(a)\;1.25\;mm \\ (b)\;1\;m \\ (c)\;2\;m \\ (d)\;2.25 \;mm $

Can you answer this question?

1 Answer

0 votes
For minima
$y= (2n-1) \large\frac{\lambda D}{d}$
$\large\frac{\lambda D}{d}=\frac{5000 \times 10^{-10} \times 1}{1 \times 10^{-3}} $$=0.5 mm$
$y= 2.25 mm$
Hence d is the correct answer.


answered Feb 13, 2014 by meena.p
edited Jul 22, 2014 by thagee.vedartham

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App