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Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
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Dissolving 120g of urea (mol.wt.60) in 1000g of water gave a solution of density 1.15g/ml.The molarity of solution is

$\begin{array}{1 1}(a)\;2.60M\\(b)\;2.05M\\(c)\;2.22M\\(d)\;1.70M\end{array}$

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Answer: 2.05 M
Density of the solution $1.15 \;g\;mL^{-1} = \large\frac{M}{V}$$ = \large\frac{1000+120}{V}$$\rightarrow V = \large\frac{1120}{1.15} $$ = 973.91 \;mL$
$\Rightarrow$ Molarity $= \large\frac{W}{M} $$ \times\large\frac {1000}{V\;mL}$$ = \large\frac{120 \times1000\times1.25}{60 \times 973.91}$$ = 2.05\; M \;$
answered Feb 13, 2014 by sreemathi.v
edited Jul 17, 2014 by balaji.thirumalai
 

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