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# The current through the battery is

$\begin {array} {1 1} (A)\;\large\frac{1}{20}A & \quad (B)\;\large\frac{1}{15}A \\ (C)\;\large\frac{1}{10}A & \quad (D)\;\large\frac{1}{5}A \end {array}$

The two outer 30 ohm resistors are in series and so effectively we have a 30 ohm resistor in parellel with a 60 ohm resistor.
The circuit is a simple combination of resistors in series and parallel.
The effective resistance in the circuit is 20 Ohms and so the   current is  2/20  which is 1/10 A
Ans : (C)

edited Sep 11, 2014