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If A and B are such events that $P(A)>o$ and $P(B)\neq 1$,then P(A|B) equals

$\begin{array}{1 1}(A)\;1-P(A|B)\quad(B)\;1+P(A|B)\quad(C)\;\frac{1-P(A\cap B)}{P(B')}\quad(D)\;P(A)|P(B)\end{array} $

1 Answer

Toolbox:
  • \(P(\bar{A}/\bar{B})=\Large\frac{p(\bar{A}\;\cap\;\bar{B})}{P(B)}\)
  • \(P(\bar{A}\cap\bar{B})\)=\(P(\overline{A\cup\;B})\)
  • =\(1-P(A\cup\;B)\)
\(P(\bar{A}/\bar{B})=\Large\frac{p(\bar{A}\;\cap\;\bar{B})}{P(B)}\)
=\(\Large\frac{1-P(A\cup\;B)}{P(\bar{B})}\)
'C'option is correct

 

answered Mar 4, 2013 by poojasapani_1
edited Mar 15, 2013 by poojasapani_1
 

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