# If A and B are such events that $P(A)>o$ and $P(B)\neq 1$,then P(A|B) equals

$\begin{array}{1 1}(A)\;1-P(A|B)\quad(B)\;1+P(A|B)\quad(C)\;\frac{1-P(A\cap B)}{P(B')}\quad(D)\;P(A)|P(B)\end{array}$

Toolbox:
• $$P(\bar{A}/\bar{B})=\Large\frac{p(\bar{A}\;\cap\;\bar{B})}{P(B)}$$
• $$P(\bar{A}\cap\bar{B})$$=$$P(\overline{A\cup\;B})$$
• =$$1-P(A\cup\;B)$$
$$P(\bar{A}/\bar{B})=\Large\frac{p(\bar{A}\;\cap\;\bar{B})}{P(B)}$$
=$$\Large\frac{1-P(A\cup\;B)}{P(\bar{B})}$$
'C'option is correct

answered Mar 4, 2013
edited Mar 15, 2013