$(a)\;2\;I_0 \\ (b)\;3\;I_0 \\ (c)\;I_0 \\ (d)\;None $

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For point $0, \theta =0$

Hence $\Delta P = d \sin \theta _0$

for small angles$ \sin \theta _0= \theta _0$

$0.57^{\circ}= (10^{-2} \;rad)$

$d \theta_0= 1mm \times (10^{-2} \;rad)$

$\qquad= 10,000 nm$

$\qquad= 20 \times (500 nm)$

=> $\Delta P= 20 \lambda$

Hence point 0 corresponds to $20th $ maxima

=>Intensity at $0=I_0$

Hence c is the correct answer

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