$\begin{array}{1 1} (A) molarity = 1.24 mol/kg, mole fraction = 0.028 \\ (B) molarity = 1.64 mol/kg, mole fraction = 0.029 \\ (C) molarity = 1.34 mol/kg, mole fraction = 0.039 \\ (D) molarity = 1.54 mol/kg, mole fraction = 0.049\end{array}$

Let's assume that we have 1 L = 1000 mL of the solution.

1.37 mol $\times$ 192.1 g/mol = 263.18 g of citric acid.

Therefore, in 1 L, we will have 1000 ml $\times$ 1.1 g/cm$^3$ = 1.1 $\times$ 10$^3$ g solution.

$\Rightarrow$ 1.1 $\times$ 10$^3$ g solution - 263.18 g citric acid = 836.82 g $H_2O$

Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution.

$\Rightarrow$ molarity = 1.37 mol / 0.83682 Kg of $H_2O$ = 1.64 mol/kg.

836.82 g of $H_2O$ / 18.0 g/mol = 46.49 mol $H_2O$

$\Rightarrow$ mole fraction of citric acid = 1.37 mol / (1.37 mol + 46.49 mol) = 0.029.

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