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# If A and B are two independent events with $P(A)=\Large \frac{3}{5}$ and $P(B)=\Large \frac{4}{9},$then $P(A\cap B)$ equals

$\begin{array}{1 1}(A)\;\frac{4}{15}\quad(B)\;\frac{8}{45}\quad(C)\;\frac{1}{3}\quad(D)\;\frac{2}{9}\end{array}$

Toolbox:
• $A\;and\;B\;are\; indipendant$
• $P(A). P(B)=P(A\;\cap\;B)$
P(A$\cap$B)=$\Large\frac{3}{5}$x$\frac{4}{9}$
=$\Large\frac{4}{15}$
$'A'\;is\; correct$

edited Mar 15, 2013