Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
0 votes

Two points $P$ and $Q$ are maintained at the potentials of $10V$ and $-4V$ respectively. The work done in moving $100$ electrons from $P$ to $Q$ is

$\begin {array} {1 1} (A)\;-19 \times 10^{-17}J & \quad (B)\;9.6 \times 10^{-17}J \\ (C)\;-2.24 \times 10^{-16}J & \quad (D)\;2.24 \times 10^{-16}J \end {array}$


Can you answer this question?

1 Answer

0 votes
$W = QdV = -100 \times 10^{-16} (-4\: -10) = 2.24 \times 10^{-16}$
Ans : (D)
answered Feb 13, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App