The current passing through the $3\Omega$ resistor is

$\begin {array} {1 1} (A)\;1\: A & \quad (B)\;2\: A \\ (C)\;3\: A & \quad (D)\;4\: A \end {array}$

We have that the potential difference across 2 ohm resistor is 4V
Hence potential difference across the $3\: ohm$ resistor is $6V.$
The current flowing through 3 ohm resistor is now 6/3  = 2 A
Ans : (B)

edited Sep 11, 2014