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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Current Electricity

If $400ohms $ of resistance is made by adding four $ 100 \: ohm $ resistances of tolerance 5%, then the tolerance of the combination is:

$\begin {array} {1 1} (A)\;5 \% & \quad (B)\;10 \% \\ (C)\;15 \% & \quad (D)\;20 \% \end {array}$

 

1 Answer

$R = 100 \pm 5$
$4R = 400 \pm 20$
Hence, the tolerance of the combination is also $ 5 \%.$
Ans : (A)
answered Feb 13, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1
 

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