logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
0 votes

If $400ohms $ of resistance is made by adding four $ 100 \: ohm $ resistances of tolerance 5%, then the tolerance of the combination is:

$\begin {array} {1 1} (A)\;5 \% & \quad (B)\;10 \% \\ (C)\;15 \% & \quad (D)\;20 \% \end {array}$

 

Can you answer this question?
 
 

1 Answer

0 votes
$R = 100 \pm 5$
$4R = 400 \pm 20$
Hence, the tolerance of the combination is also $ 5 \%.$
Ans : (A)
answered Feb 13, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...