Answer: There is no deviation from Raoult's law

Given, Moles of X = 1 mole, Moles of Y = 2 moles

Partial pressure of X = $P^0_X \times x_X = 150\; torr \times \frac{1}{1+2} = 150 \times \frac{1}{3} \; torr$

Partial pressure of Y = $P^0_X \times x_X = 240\; torr \times \frac{2}{1+2} = 240 \times \frac{2}{3} \; torr$

So, the total presssure is P=$P_X^0x_X+P_Y^0x_Y$

$\Rightarrow 150\times \large\frac{1}{3}$$+240\times \large\frac{2}{3}$

$\Rightarrow 50+60$

$\Rightarrow 210$ torr

Given total pressure of the solution = 210 mm

Since the solution is obeying Raoult's law. Hence there is no deviation from the Raoult's law.