$\begin{array}{1 1}(a)\;\text{the enthalpy of mixing is zero}\\(b)\;\text{the volume of mixing is zero}\\(c)\;\text{none of these}\\(d)\;\text{(a) and (b)}\end{array}$

- The concept of an ideal solution depends on the use of its colligative properties.
- An ideal solution is a solution in which the enthalpy of solution is zero. $\Delta H_{solution} = 0$. The more the change in enthalpy is near zero, the more it is ideal.
- If the enthalpy of mixing is zero, the change in Gibbs energy of mixing can be determined by the change in entropy.. Therefore, $\Delta S =0$

Since, for an ideal solution, $\Delta S =0 $, there is no change in volume. $\Delta V=0$

$\Delta H=0$

$\Delta V=0$

Hence (d) is the correct answer.

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