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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Solutions

Match the column-I and column-II

Column-I Column-II
(1) Molarity (p) Equivalent per liter
(2) Normality (q) does not have units
(3) ppm (r) moles per liter
(4) Molality (s) moles per kg


$\begin{array}{1 1}(a)\;(1)\rightarrow (p),(2)\rightarrow (r),(3)\rightarrow (q),(4)\rightarrow (s)\\(b)\;(1)\rightarrow (q),(2)\rightarrow (p),(3)\rightarrow (r),(4)\rightarrow (s)\\(c)\;(1)\rightarrow (s),(2)\rightarrow (p),(3)\rightarrow (q),(4)\rightarrow (r)\\(d)\;(1)\rightarrow (r),(2)\rightarrow (p),(3)\rightarrow (q),(4)\rightarrow (s)\end{array}$

1 Answer

  • $Molarity =\large \frac{\text{Moles of solute}}{\text{Volume of solution in Litres}}$
  • $Molality =\large \frac{\text{Moles of solute}}{\text{Mass of solvent in kg}}$
  • The normality of a solution is the gram equivalent weight of a solute per liter of solution.
  • parts per million = $\large \frac{\text{grams of solute}}{\text{grams of solution}} \times 10^6$
The unit of the properties listed in Column I is enlisted below:
Molarity $\rightarrow$ moles/lit
Normality $\rightarrow$ Equivalent/lit
Molality $\rightarrow$ moles/kg
ppm $\rightarrow$ does not have units
Hence (d) is the correct answer.
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