Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A particle of charge -q and mass m moves in a circle of radius r arround an infinitely long line charge of linear density $\;+\lambda\;$ . Then time period will be

$(a)\;2 \pi r \sqrt{\large\frac{m}{2 k \lambda q}}\qquad(b)\;2 \pi \sqrt{\large\frac{m r^3}{2 k \lambda q}}\qquad(c)\;\large\frac{1}{2 \pi r}\;\sqrt{\large\frac{2 k \lambda q}{m}}\qquad(d)\;\large\frac{1}{2 \pi r}\;\sqrt{\large\frac{m}{2 k \lambda q}}$

Can you answer this question?

1 Answer

0 votes
Answer : (a) $\;2 \pi r \sqrt{\large\frac{m}{2 k \lambda q}}$
Explanation :
Centripetal force = Eq
$T=\large\frac{2 \pi r}{v}=2 \pi r \sqrt{\large\frac{m}{2\;k\;\lambda\;q}}\;.$
answered Feb 14, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App