$\begin{array}{1 1}(a)\;352torr\\(b)\;312torr\\(c)\;13.44torr\\(d)\;14.12torr\end{array}$

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Relative lowering of V.P

$\large\frac{P^0-P}{P^0}$$=X_i$=mole fraction

$P^0-P=\Delta P=X_i\times P^0$

$\Rightarrow \big(\large\frac{1}{1+\Large\frac{1000}{18}}\big)$$\times 760$

$\Rightarrow \big(\large\frac{1}{1+55.55}\big)$$\times 760$

$\Rightarrow 0.0176\times 760$

$\Rightarrow 13.44$

Hence (c) is the correct answer.

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