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Positive deviations from ideal gas behaviour takes place because


$\begin{array}{1 1} (a)\;Molecular\;interaction\;between\;atoms\;and\;\large\frac{PV}{nRT} > 1\\(b)\;Molecular\;interaction\;between\;atoms\;and\;\large\frac{PV}{nRT} < 1\\(c)\;Finite\;size\;of\;atoms\;and\;\large\frac{PV}{nRT} > 1\\(d)\;Finite\;size\;of\;atoms\;and\;\large\frac{PV}{nRT} < 1\end{array}$

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For positive deviations Z > 1 i.e the conditions when repulsive forces predominants
hence answer is (a)
answered Feb 14, 2014 by sharmaaparna1

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