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Home  >>  CBSE XII  >>  Math  >>  Probability
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Let A and B be two events .Such that $P(A)=\Large\frac{3}{8}$,$P(B)=\Large \frac{5}{8}$ and $P(A\cup B)=\Large\frac{3}{4}$.Then P(A|B).P(A|B) is equal to

$\begin{array}{1 1}(A)\;\frac{2}{5}\\(B)\;\frac{3}{8}\\(C)\;\frac{3}{20}\\(D)\;\frac{6}{25}\end{array} $

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1 Answer

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\(p(A\;\cap\;B)=\Large\frac{3}{8}\)+\(\frac{5}{8}-\frac{3}{4}\;=\;\frac{1}{4}\)
\(P(A/B)=\Large\frac{\frac{1}{4}}{\frac{5}{8}}=\frac{2}{5}\)
\((A\;\cap\;B)=\Large\frac{5}{8}-\frac{1}{4}\;=\;\frac{3}{8}\)
\(P(A/B)=\Large\frac{\frac{3}{8}}{\frac{5}{8}}\;=\;\frac{6}{25}\)
\('D\;'option\; is \;correct\)
answered Feb 22, 2013 by poojasapani_1
edited Jun 4, 2013 by poojasapani_1
 

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