$(a)\;23.62atm\qquad(b)\;24.32atm\qquad(c)\;26atm\qquad(d)\;25.215atm$

Given

Mole of $O_2$ in a mixture = $\large\frac{4}{32}$

Mole of $H_2$ in mixture = $\large\frac{2}{2} =1$

Total mole present in mixture = 1+$\large\frac{4}{32} = \large\frac{36}{32}$

Also T = 273 K V = 1 litre

We have PV = nRT

$P\times1 = \large\frac{36}{32}\times0.0821\times273$

P = 25.215 atm

Hence answer is (d)

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