logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
0 votes

pH of a 0.1M monobasic acid is found to be 2.Hence its osmotic pressure at a given temp T is

$\begin{array}{1 1}(a)\;0.11RT\\(b)\;0.1RT\\(c)\;0.01RT\\(d)\;1.1RT\end{array}$

Can you answer this question?
 
 

2 Answers

0 votes
Osmotic pressure $(\pi)=CRT$
Where $C$=Molarity of solution
$\therefore \pi=0.1RT$
Hence (b) is the correct answer.
answered Feb 14, 2014 by sreemathi.v
This answer is WRONG.
[H+]=C*alpha
Therefore alpha=0.01/0.1=0.1
Now,
i=alpha +1
i=0.1+1
i=1.1
Osmotic pressure
=CRTi
=0.1RT1.1
=0.11RT
Why isn't vant hoff factor used ..??
 
0 votes

[H+]=C*alpha
Therefore alpha=0.01/0.1=0.1
Now,
i=alpha +1
i=0.1+1
i=1.1
Osmotic pressure
=CRTi
=0.1RT1.1
=0.11RT

answered May 30, 2015 by het.thakkar809
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...