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Questions  >>  JEEMAIN and NEET  >>  Chemistry  >>  Solutions
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Mole fraction of the component 'A' in vapour phase is X and mol fraction of component 'A' in liquid mixture is Y $(P_A^0$=vapour pressure of pure A,$P_A^0$=vapour pressure of pure B) then total vapour of the liquid mixture is

$\begin{array}{1 1}(a)\;\large\frac{P_B^0Y}{X}\\(b)\;\large\frac{P_B^0X}{Y}\\(c)\;\large\frac{P_A^0X}{Y}\\(d)\;\large\frac{P_A^0Y}{X}\end{array}$

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